(2x^2)+(x)+1=0

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Solution for (2x^2)+(x)+1=0 equation: 


Simplifying
(2x2) + (x) + 1 = 0
(2x2) + x + 1 = 0

Reorder the terms:
1 + x + (2x2) = 0

Solving
1 + x + (2x2) = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
0.5 + 0.5x + x2 = 0

Move the constant term to the right:

Add '-0.5' to each side of the equation.
0.5 + 0.5x + -0.5 + x2 = 0 + -0.5

Reorder the terms:
0.5 + -0.5 + 0.5x + x2 = 0 + -0.5

Combine like terms: 0.5 + -0.5 = 0.0
0.0 + 0.5x + x2 = 0 + -0.5
0.5x + x2 = 0 + -0.5

Combine like terms: 0 + -0.5 = -0.5
0.5x + x2 = -0.5

The x term is x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
0.5x + 0.25 + x2 = -0.5 + 0.25

Reorder the terms:
0.25 + 0.5x + x2 = -0.5 + 0.25

Combine like terms: -0.5 + 0.25 = -0.25
0.25 + 0.5x + x2 = -0.25

Factor a perfect square on the left side:
((x) + 0.5)((x) + 0.5) = -0.25

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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